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AnonymousBoba Foxx 06 Feb 2013 18:57
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Boba Foxx
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If it is inverted binary, then this should do it:

:Delvar B
:Input "String?",str1
:if 5≠length(str1
:stop
For(Z,1,5
:B+1(sub(str1,Z,1)=2^(Z-1
end

should work :)

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