This is a funny page… Anyone knowing more of this kind?
Date: 23 Oct 2008 16:08
Number of posts: 11
RSS: New posts
This isn't humorous, but I can prove that 1+1 is inequal to 2. My friend showed this to me.
i=i, as in the square root of -1
Here's the proof:
1+i is inequal to 2
Can anyone disprove this in any way other than reversing the process? I know that it is wrong, and that there is a trick to it. I just want to
see if someone can find it.
Between lines 2–3, why on earth is √1 assumed to equal -√(-1)(1+i)?
And then you assumed that √(-1)(1+i) = i(1+i) = i+i² is somehow equal to -i… I just don't get it.
Indeed, your assumptions are wrong, I think.
To answer Weregoose's question; When some of my friends, and I were working on this, my friend pointed out an
error in our calculations,(the area that weregoose is questioning), and he quickly fixed it. It was an error in copying
on my part.
ex. If the sqrt(X)-sqrt(-X) is assumed to be equal to sqrt(X)+sqrt(X), and we substitute 2 for X, then we get this
which is obviously not true.
The only way to make the equation:
true, is to multiply the right side by (1+i)
This is true for,(I think), all numbers.
Try it on your calculator.
The place where the equation is wrong, in fact, is where the assumption 1=sqrt(1) is made. This would then have to
be true for all numbers, not just 1, for the proof to be valid.
I should have put:
for line 3. Sorry.
Well if you have (1 + i)(sqrt(1)-sqrt(-1)) as line three, you have(1)
So it works.
You know, this is one of the only places where people will argue about this. (It's not a bad thing,
though) Most people will just say: "I know 1+1 is 2, so shut up, nerd.", or something similar.
There is also the obvious 1=2 problem
- a2=ab (multiply by a)
- a2-b2=ab-b2 (subtract b2)
- (a+b)(a-b)=b(a-b) (Factor)
- a+b=b (divide by a-b)
- 2b=b (substitute b into a since a=b)
- 2=1 (divide by b)