peg1: (0,0) coordinates

peg2: (7,1) coordinates

if you draw a line between the pegs, and the weigth is in the midle, you draw the peg's coordinates one a paper

then you draw a circle 5m width

congrulations! you have calucated the exact locaton/angle of the weight!

]]>At this point, drawing a diagram helps. Anyway, since you have the lengths of all three sides, you can find angle A and angle B using the law of cosines. (Check Wikipedia if you don't remember the law of cosines.) Basically, the law of cosines takes three side lengths and an angle. We can solve for the angle by plugging in the right side lengths and solving.

Once you have angle A and angle B (note, they should be the same, because ABC is isosceles), finding the angle between AC and a horizontal line (which is what we want) is a simple matter. First find the angle of AB by taking the arctangent of the slope. Then do some angle addition/subtraction. Same goes for angle of BC.

Sorry if I'm not too clear on this last step. Do you know how to split vectors (forces) into components given their angle and magnitude?

]]>doesn't start for a while. ]]>

(Note: I haven't taken physics; I'm more of a math guy, so please excuse any improper notation or conventions I use. =D) There are three forces acting on the weight - gravity, the pulling from the segment of string attached to the first peg (call it peg A), and the pulling from the segment of string attached to the other peg (peg B). Call these forces F_g, F_a, and F_b, respectively. We want to find all these forces, because F_a is equal and opposite to the force the string applies on peg A, which is what you're looking for.

F_g, F_a, and F_b must sum to zero, because the weight isn't moving. However, we can't solve for F_a and F_b, because we don't know what direction the forces are applied in. We need to know the angles of each segment of string.

Note that since the string is stretched straight, the two pegs and the weight (more specifically, the point where the weight attaches to the string) form a triangle. You can find all the side lengths of the triangle, so you can solve the triangle and find the angles of the two strings using trigonometry.

Once you find the angles, just split the forces into components, sum to 0, and solve.

]]>The rope has to be loose since it is longer than the distance between the two pegs. Also, Force is mass times gravity, so we know the weight of the weight. The opposite of that force is being applied to the rope (but if it has no mass, it doesn't technically exist). I would suggest drawing a diagram. But truthfully, I have no idea. I'm taking physics, but we're not quite here yet.

~

There are 2 pegs in a wall, one is 7 meters away horizontally, and 1 meter vertically, from the other. A 25 kg weight is tied to the middle of a

10 meter long rope, and the ends are tied to the pegs. I need to calcuate the force being applied on each peg, by the rope. This is all

assuming that the rope has no mass. I don't want the answer, I just need some hints on how to do it.