Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help Posts in the discussion thread "Tic Tac To Help" - Hey I need some help with my coding I get a syntax error when I run the program I copied it directly off of http://tibasicdev.wikidot.com/tic-tac-to Wed, 13 May 2026 03:38:39 +0000 http://tibasicdev.wikidot.com/forum/t-12646486#post-4392579 Re: Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help#post-4392579 Tue, 08 Oct 2019 13:32:27 +0000 3338172 Yeah, that means you typed in a [, A, then a ].

]]> http://tibasicdev.wikidot.com/forum/t-12646486#post-4392444 Re: Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help#post-4392444 Tue, 08 Oct 2019 11:27:04 +0000 Vomindoraan 5712009 Will use next time

]]> http://tibasicdev.wikidot.com/forum/t-12646486#post-4392051 Re: Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help#post-4392051 Tue, 08 Oct 2019 03:28:31 +0000 3338172 Good to hear things work!

A little advice: you can use the 'edit' button to edit your posts to keep threads cleaner and easier to read. :)

]]> http://tibasicdev.wikidot.com/forum/t-12646486#post-4391949 Re: Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help#post-4391949 Tue, 08 Oct 2019 01:23:41 +0000 Vomindoraan 5712009 - On the A
- 2nd a
- I made sure and everything was typed correctly
- Thx
- Is it compatible with the ti-83?

[Posts merged by moderator]

]]> http://tibasicdev.wikidot.com/forum/t-12646486#post-4391756 Re: Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help#post-4391756 Mon, 07 Oct 2019 22:10:30 +0000 Trenly 1905506 Make sure you're using the matrix variable [A] and not just typing out the characters [ A ]

]]> http://tibasicdev.wikidot.com/forum/t-12646486#post-4391480 Re: Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help#post-4391480 Mon, 07 Oct 2019 16:36:55 +0000 3338172 I didn't receive any errors, 0→A:0identity(3→[A] works fine on my TI-84+, with the result of:

[[0 0 0] [0 0 0] [0 0 0]]

Where does the cursor bring you to on that line of code?

]]> http://tibasicdev.wikidot.com/forum/t-12646486#post-4391187 Re: Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help#post-4391187 Mon, 07 Oct 2019 12:36:33 +0000 Vomindoraan 5712009 The first one
:0→A:0identity(3→[A]

]]> http://tibasicdev.wikidot.com/forum/t-12646486#post-4389227 Re: Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help#post-4389227 Sat, 05 Oct 2019 23:43:19 +0000 Trenly 1905506 Which line are you getting the syntax error on? That page hasn't been modified since 2012, so it is most likely that you typed something in wrong if you didn't use the download.

]]> http://tibasicdev.wikidot.com/forum/t-12646486#post-4389178 Tic Tac To Help http://tibasicdev.wikidot.com/forum/t-12646486/tic-tac-to-help#post-4389178 Sat, 05 Oct 2019 21:58:23 +0000 Vomindoraan 5712009 This the code I'm using on the ti-83:

:0→A:0identity(3→[A] :1-2int(2rand→B :"+++ :ClrHome :Disp Ans,Ans,Ans :Repeat 0 :Repeat Ans :.1getKey→K :End :If 2Ans=9:Goto Q :iPart(Ans)-6→C :10fPart(K)-1 :If max(2≤abs({C,Ans}-2:End :If [A](C,Ans:End :Output(C,Ans,sub("X O",B+2,1 :B→[A](C,Ans :For(C,0,1 :[A]T→[A] :For(D,1,3 :Matr►list([A],D,T :If min(∟T=B:Goto Q :End :If min(B=seq([A](abs(4C-X),X),X,1,3 :Goto Q :End :-B→B:IS>(A,9 :End :Lbl Q :"TIE! :If A≠9 :sub("X O",B+2,1)+" WINS! :If 2K≠9 :Pause Ans :ClrHome:"
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