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		<title>Parallel Circuits Equivalent Resistance.</title>
		<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance</link>
		<description>Posts in the discussion thread &quot;Parallel Circuits Equivalent Resistance.&quot; - Can you help me optimize?</description>
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		<lastBuildDate>Fri, 12 Jun 2026 17:33:54 +0000</lastBuildDate>
		
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2394951</guid>
				<title>Re: Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2394951</link>
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				<pubDate>Wed, 21 Oct 2015 19:23:05 +0000</pubDate>
				<wikidot:authorName>Trenly</wikidot:authorName>				<wikidot:authorUserId>1905506</wikidot:authorUserId>				<content:encoded>
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						 <p>Please don't revive dead topics</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2394896</guid>
				<title>Re: Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2394896</link>
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				<pubDate>Wed, 21 Oct 2015 17:54:01 +0000</pubDate>
				<wikidot:authorName>CortEnis</wikidot:authorName>				<wikidot:authorUserId>2307382</wikidot:authorUserId>				<content:encoded>
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						 <p>I didn't work much upon it but as per my little experience i think it is right if you could request a list by using Input L1 and omit the expr(&quot;{&quot;+Str1) but the user will have to manually put in the bracket.<br /> Also, a list variable is destroyed. Usually, destroying strings are favorable to destroying lists.</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286678</guid>
				<title>Re: Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286678</link>
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				<pubDate>Wed, 06 May 2015 02:35:14 +0000</pubDate>
				<wikidot:authorName>Trenly</wikidot:authorName>				<wikidot:authorUserId>1905506</wikidot:authorUserId>				<content:encoded>
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						 <p>The speed and size work well. I think the string is a pretty good way of doing it.</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286669</guid>
				<title>Re: Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286669</link>
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				<pubDate>Wed, 06 May 2015 02:26:31 +0000</pubDate>
				<wikidot:authorName>Electromagnet8</wikidot:authorName>				<wikidot:authorUserId>1820230</wikidot:authorUserId>				<content:encoded>
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						 <p>You would still be destroying a list variable&#8230;.</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286660</guid>
				<title>Re: Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286660</link>
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				<pubDate>Wed, 06 May 2015 02:08:33 +0000</pubDate>
				<wikidot:authorName>Toothless the Dragon</wikidot:authorName>				<wikidot:authorUserId>1795227</wikidot:authorUserId>				<content:encoded>
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						 <p>Copy it to a temp variable (like L2) and use that maybe?</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286650</guid>
				<title>Re: Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286650</link>
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				<pubDate>Wed, 06 May 2015 01:51:08 +0000</pubDate>
				<wikidot:authorName>Electromagnet8</wikidot:authorName>				<wikidot:authorUserId>1820230</wikidot:authorUserId>				<content:encoded>
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						 <p>You could request a list by using Input L1 and omit the expr(&quot;{&quot;+Str1) but the user will have to manually put in the bracket. Also, a list variable is destroyed. Usually, destroying strings are favorable to destroying lists.</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286644</guid>
				<title>Re: Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286644</link>
				<description></description>
				<pubDate>Wed, 06 May 2015 01:44:09 +0000</pubDate>
				<wikidot:authorName>Toothless the Dragon</wikidot:authorName>				<wikidot:authorUserId>1795227</wikidot:authorUserId>				<content:encoded>
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						 <p>Ooh nice, good job.</p> <p>Would it be easier to input a list instead though?</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286438</guid>
				<title>(no title)</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286438</link>
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				<pubDate>Tue, 05 May 2015 20:19:57 +0000</pubDate>
				<wikidot:authorName>Michael2_3B</wikidot:authorName>				<wikidot:authorUserId>1974546</wikidot:authorUserId>				<content:encoded>
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						 <p>Nice, although you could just do E+A^-1-&gt;E. Also, since C is no longer used, you do not need to do &quot;DelVar C&quot;.</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286425</guid>
				<title>Re: Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286425</link>
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				<pubDate>Tue, 05 May 2015 20:05:24 +0000</pubDate>
				<wikidot:authorName>Trenly</wikidot:authorName>				<wikidot:authorUserId>1905506</wikidot:authorUserId>				<content:encoded>
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						 <p>The input goes off of my screen, but that is easy to fix. Thank you.</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286424</guid>
				<title>(no title)</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286424</link>
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				<pubDate>Tue, 05 May 2015 20:04:55 +0000</pubDate>
				<wikidot:authorName>Trenly</wikidot:authorName>				<wikidot:authorUserId>1905506</wikidot:authorUserId>				<content:encoded>
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						 <p>Thanks toothless.</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286407</guid>
				<title>Re: Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286407</link>
				<description></description>
				<pubDate>Tue, 05 May 2015 19:42:19 +0000</pubDate>
				<wikidot:authorName>lirtosiast</wikidot:authorName>				<wikidot:authorUserId>2005367</wikidot:authorUserId>				<content:encoded>
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						 <div class="code"> <pre><code>Input &quot;Enter resistor values, separated by commas&quot;, Str1 sum(expr(&quot;{&quot;+Str1) ֿ¹) ֿ¹ Disp Ans,round(Ans,2</code></pre></div> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286401</guid>
				<title>(no title)</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286401</link>
				<description></description>
				<pubDate>Tue, 05 May 2015 19:32:05 +0000</pubDate>
				<wikidot:authorName>Toothless the Dragon</wikidot:authorName>								<content:encoded>
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						 <p>Input &quot;Repeat (n) times:&quot;,N<br /> Delvar E<br /> For(B,1,N<br /> Input &quot;R:&quot;,A<br /> A^-1<br /> E+Ans-&gt;E<br /> Delvar ADelvar C<br /> End<br /> Disp E^-1, round(E^-1,2)<br /> &quot;</p> <p>About all I can see, it's pretty darn optimized! The last part is a stylistic choice, just removes the &quot;Done&quot; statement.</p> 
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				<guid>http://tibasicdev.wikidot.com/forum/t-1188128#post-2286367</guid>
				<title>Parallel Circuits Equivalent Resistance.</title>
				<link>http://tibasicdev.wikidot.com/forum/t-1188128/parallel-circuits-equivalent-resistance#post-2286367</link>
				<description></description>
				<pubDate>Tue, 05 May 2015 18:31:36 +0000</pubDate>
				<wikidot:authorName>Trenly</wikidot:authorName>				<wikidot:authorUserId>1905506</wikidot:authorUserId>				<content:encoded>
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						 <p>I wrote a program for the formula:</p> <div class="code"> <pre><code>(1/Rt)=(1/R1)+(1/R2)+(1/Rn) //I don't have time to use subscripts right now</code></pre></div> <br /> Here is my current code: <div class="code"> <pre><code>Input &quot;Repeat (n) times:&quot;,N //input number of resistors in parallel 1-&gt;B //reset the loop variable Delvar E //clear the current answer For(B,1,N //repeat depending on how many resistors you have Input &quot;R:&quot;,A //input the resistance in ohms of an individual resistor A^-1 -&gt; C //I am using the inverse button here E+C-&gt;E //take the total and add the resistance Delvar ADelvar C //remove any source of error End //end the for loop Disp E^-1 //display the correct answer Disp round(E^-1,2) //display a rounded answer</code></pre></div> <br /> How can I optimize this code?
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