`Prompt M 1+min(π^π^π,abs(M→M ln(Ans→A For(I,0,randInt(7,33 M→C:A+M→M:C→A End int(π(e^(M/A)-1`

But yes, something like that would work (only 7 bytes, plus one for the line return), and is functionally identical to:

`Input M 12-0M`

`:Input M :Ans0+12`

`Input M 12 //invalid, no calculations`

`Input M 12-fPart(M`

`Input M 12-iPart(Mˉ¹`

`Input M 12-0M`

`Input M real(12+Mi //this is the imaginary i, [2nd]+[.]`

`12not(not(M //only works if M is not 0`

`Input M 12log(M,M //note that this should work on any calculator with OS 2.43+, but may not work on WabbitEmu`

`Input M min(12,max(12,M`

`Input M 12(M=M`

`Input M 12+iPart(sin(M //This one only works in radian mode, and when M≠nπ/2 where n is odd. However, since pi is irrational, and only integers are allowed as input, this should always work`

`Input M nDeriv(12M,M,1`

`Input M 12(M nCr M`

`Input M 12(M nPr 0`

`Input M median({12,12,M`

`Input M 12+DeltaList({M,M`

`Input M 12+MgetKey`

`Input M 12+M^0`

`Input M 12M/M`

`Input M 10-M→V 2+M V+Ans`

Let's break this code down. For this example, let's say the input is 21 (M=21). For the first part of the code, 10-M=-11. The value -11 is stored into V.

Then, 2 is added to the input value. 2+M is 23.

Lastly, we add the variables V and Ans. So, we get 12 out of these because -11+23=12.

**Note:** This is not the best code, will output 12 for most values. Too big values will NOT equal 12. You may enter values from -9999999999999 to 9999999999999 (13 digits). Program size: **14 bytes**

- Make your code as short as possible, needs to be less than 100 bytes. The program name does not count.
**Do NOT use my code, use your own.**- Make sure the code is usable on any programmable-friendly calculator.
- Must include any value with the Input command (must be a whole integer, no fractions or decimals) with an output of 12.
- Do not assume you will get the award immediately. Give others a chance.
- You must use calculations. This code is considered cheating, and will not qualify:

`Input M 12`

The person who creates the best code will be rewarded with a 1-night Red Box movie gift card! Give this a shot!

If you win, you will receive a private message with the code attached. If you have any questions, please contact me, your site administrator, or moderator.

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